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⌊aj⌋xj + fj≤f0 (2007)
Ashutosh Mahajan
,
S {(x
Abstract
n� j=1 ajxj + Substitute aj = ⌊aj ⌋ + fj, b = ⌊b ⌋ + f0. Then,
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http://coral.ie.lehigh.edu/~ipsem/talks/2006_07/asm4_valid_mips.pdf
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